Answer
$ -8y^{12}$
Work Step by Step
$-(2x^0y^4)^3$
$= -(2^3x^{0\times3}y^{4\times3})$
$ = -(8x^0y^{12})$
$ = -8y^{12}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 32: 28
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