Answer
$\frac{-125n^{12}}{r^2}$
Work Step by Step
The rules $(\frac{a}{b})^n = \frac{a^n}{b^n}$, $(a^m)^n = a^{mn}$.
$\frac{(-5n^4)^3}{r^2} = \frac{(-5)^3 n^{4\times3}}{r^2} = \frac{-125n^{12}}{r^2}$
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