Answer
$\frac{p^{8}}{q^2}$.
Work Step by Step
The rule $(\frac{a}{b})^n = \frac{a^n}{b^n}$.
$(\frac{p^4}{q^1})^2 = \frac{p^{4\times2}}{q^{1\times2}} = \frac{p^{8}}{q^2}$.
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