Answer
true
Work Step by Step
RECALL:
$a^m \cdot a^n = a^{m+n}$
Thus,
$y^2 \cdot y^5 = y^{2+5} = y^7$
Therefore, the given statement is true.
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 32: 7
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