Answer
$(-\infty, -1]$
Refer to the attached image below for the graph.
Work Step by Step
The given inequality can be written as
$\\4-3x \le -1(1+8x)$
Distribute $-1$ to have:
$\\4-3x \le -1 -8x$
Add $8x$ to both sides to have:
$\\4-3x+8x \le -1-8x+8x
\\4+5x \le -1$
Subtract 4 to both sides to have:
$\\4+5x-4 \le -1 - 4
\\5x \le -5$
Divide 5 to both sides to have:
$x \le -\frac{5}{5}
\\x \le -1$
