Answer
(-$\infty$,-3] $\cup$ [3,$\infty$)
Work Step by Step
$x^{2}$ $\geq$ 9
$x^{2}$-9 $\geq$ 0
(x+3)(x-3) $\geq$ 0
Factors are zero when x=3 or -3, endpoints satisfy the inequality
, plug in numbers from intervals to decide which of them satisfy the inequality.
