Answer
$\sin\theta=\frac{y}{r}=\frac{-3}{5}$
$\cos\theta=\frac{x}{r}=\frac{-4}{5}$
$\tan\theta=\frac{y}{x}=\frac{-3}{-4}$
$\csc\theta=\frac{r}{y}=\frac{5}{-3}$
$\sec\theta=\frac{r}{x}=\frac{5}{-4}$
$\cot\theta=\frac{x}{y}=\frac{-4}{-3}$
Work Step by Step
$x=-4$
$y=-3$
$r=\sqrt{(-3)^{2}+(-4)^{2}}=\sqrt {9+16}= 5$
