Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 26: 50

Answer

$\sin\theta=\frac{y}{r}=\frac{6}{\sqrt {61}}=\frac{6\sqrt {61}}{61}$ $\cos\theta=\frac{x}{r}=\frac{5}{\sqrt {61}}=\frac{5\sqrt {61}}{61}$ $\tan\theta=\frac{y}{x}=\frac{6}{5}$ $\csc\theta=\frac{1}{\sin\theta}=\frac{\sqrt {61}}{6}$ $\sec\theta=\frac{1}{\cos\theta}=\frac{\sqrt {61}}{5}$ $\cot\theta=\frac{1}{\tan\theta}=\frac{5}{6}$

Work Step by Step

$x=5$ $y=6$ $r=\sqrt {(5)^{2}+(6)^{2}}=\sqrt {25+36}=\sqrt {61}$
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