Answer
Yes.
Work Step by Step
For a spontaneous process,
$\Delta S_{sys}+\Delta S_{surr}\gt0$
Here, $\Delta S_{sys}+\Delta S_{surr}=(105\,J/K)+(-95\,J/K)=10\,J/K\gt0$
Therefore, the process is spontaneous.
Physical Chemistry: Thermodynamics, Structure, and Change
by Atkins, Peter; de Paula, Julio
Published by
W. H. Freeman
ISBN 10:
1429290196
ISBN 13:
978-1-42929-019-7
Chapter 3 - Topic 3A - Entropy - Exercises - Page 149: 3A.1(b)
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