Answer
(i) 366 J/K
(ii) 309 J/K
Work Step by Step
Recall: For an isothermal process, $\Delta S=\frac{q_{rev}}{T}$
(i) $\Delta S=\frac{100\times10^{3}\,J}{(0+273.15)K}=366\,J/K$
(ii) $\Delta S=\frac{100\times10^{3}\,J}{(50+273.15)K}=309\,J/K$
Physical Chemistry: Thermodynamics, Structure, and Change
by Atkins, Peter; de Paula, Julio
Published by
W. H. Freeman
ISBN 10:
1429290196
ISBN 13:
978-1-42929-019-7
Chapter 3 - Topic 3A - Entropy - Exercises - Page 149: 3A.3(a)
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