Physical Chemistry: Thermodynamics, Structure, and Change

Published by W. H. Freeman
ISBN 10: 1429290196
ISBN 13: 978-1-42929-019-7

Chapter 3 - Topic 3A - Entropy - Exercises - Page 149: 3A.11(b)

Answer

(i) $104.6\,J\,K^{-1}mol^{-1}$ (ii) $-104.6\,J\,K^{-1}mol^{-1}$

Work Step by Step

(i) $\Delta S_{vap}=\frac{\Delta H_{vap}}{T_{b}}=\frac{35.27\times1000\,J\,mol^{-1}}{(64.1+273.15)K}=104.6\,J\,K^{-1}mol^{-1}$ (ii) $\Delta S_{surr}=-\Delta S_{sys}$ $\implies \Delta S_{surr}=-\Delta S_{vap}=-104.6\,J\,K^{-1}mol^{-1}$
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