Answer
0.482 J/K
Work Step by Step
Recall that when the temperature is constant, $\Delta S=nR\ln\frac{V_{f}}{V_{i}}$
$\implies \Delta S=(\frac{4.00\,g}{28.0\,g/mol})(8.314\,J\,mol^{-1}K^{-1})(\ln\frac{750\,cm^{3}}{500\,cm^{3}})$
$=0.482\,J/K$
Physical Chemistry: Thermodynamics, Structure, and Change
by Atkins, Peter; de Paula, Julio
Published by
W. H. Freeman
ISBN 10:
1429290196
ISBN 13:
978-1-42929-019-7
Chapter 3 - Topic 3A - Entropy - Exercises - Page 149: 3A.5(b)
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