Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 1 - Exercises and Problems - Page 13: 44

Answer

$12.054\space h$

Work Step by Step

We can write, New rotation period = previous rotation period - decreased time $\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space =\space 12.404\space h\space -\space 21\space min$ Now we have to convert minutes into hours. We know 1 h = 60 min, so we can use the conversion factor 1 h / 60 min and give the value as follows. $21\space min\space=\space 21\space min\space \times\space(\frac{1\space h}{60\space min})=0.35\space h$ Therefore, $New\space rotation\space period = 12.404\space h\space -\space 0.35\space h $ $\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space \space \space \space \space \space = 12.054\space h$
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