Answer
House generated more electrical energy than it consumed
Work Step by Step
Given that,
Total energy generated by solar panels = 3849 kWh
We know, 1 kWh = 3.6 MJ. So we can multiply 3849 by 3.6 MJ/kWh to convert the value into J as follows.
Total energy generated by solar panels $= 3849\space kWh\times\frac{3.6\space MJ}{kWh}$
$\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space= 13856.4\space MJ\space-(1)$
Total time taken to produce the energy = 1 year
We know, 1 year $=365\times24\times3600\space s= 31536\times10^{3}\space s\space -(2)$
$(1)\div(2)=\gt$
Average rate of solar power generation(P) $=\frac{13856.4\space MJ}{31536\times10^{3}\space s}$
$\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space P\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space=\frac{13856.4\times10^{6}}{31536\times10^{3}}\space J/s$
$\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space P\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space=$ 439 W
$P\gt392\space W$
Therefore, the house generated more electrical energy than it consumed.
