Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 1 - Exercises and Problems - Page 13: 47

Answer

$3\space \times\space 10^{6}$ cows were required.

Work Step by Step

From the resources, we can find the milk requirement per year in US $=30\space \times 10^{9}\space kg\space - (1)$ Average dairy cow milk production $=10^{4}\space kg\space -\space (2)$ $(1)/(2)$ we can get, The no. of dairy cows requirement $=\frac{30\times10^{9}\space kg}{10^{4}\space kg}=30\space \times10^{(9-4)}$ $\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space=3\times10^{6}$
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