Answer
$\frac{x+1}{x-1}, x\ne0, x\ne1$
Work Step by Step
$\frac{x^2-1}{x}*\frac{x}{(x-1)^2}=\frac{(x-1)(x+1)}{x}*\frac{x}{(x-1)^2}=\frac{x+1}{x-1}$
(Cancel common factors from numerator and denominator)
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.5 - Rational Expressions - Exercises - Page 49: 52
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