Answer
$\frac{2x^2(x-1)-5}{(x-1)^{\frac{1}{2}}}=\frac{2x^3-2x^2-5}{(x-1)^{\frac{1}{2}}}$
Work Step by Step
$2x^2(x-1)^{\frac{1}{2}}-5(x-1)^{-\frac{1}{2}}=(x-1)^{-\frac{1}{2}}[2x^2(x-1)^{\frac{1}{2}-(-\frac{1}{2})}-5]=\frac{2x^2(x-1)-5}{(x-1)^{\frac{1}{2}}}=\frac{2x^3-2x^2-5}{(x-1)^{\frac{1}{2}}}$
