Answer
$\dfrac{-1}{t^2\sqrt{t^2+1}}$
Work Step by Step
$\dfrac{\frac{t^2}{\sqrt{t^2+1}}-\sqrt{t^2+1}}{t^2}=\dfrac{\frac{t^2}{\sqrt{t^2+1}}-\frac{t^2+1}{\sqrt{t^2+1}}}{t^2}=\dfrac{\frac{-1}{\sqrt{t^2+1}}}{t^2}=\dfrac{-1}{t^2\sqrt{t^2+1}}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.5 - Rational Expressions - Exercises - Page 49: 54
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