Answer
$\frac{2x-1}{2x}, x\ne0$
Work Step by Step
Canceling common terms and using exponent rules, we find:
$\frac{\sqrt x-\frac{1}{2\sqrt x}}{\sqrt x}=\frac{\frac{2x-1}{2\sqrt x}}{\sqrt x}=\frac{2x-1}{2x}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.5 - Rational Expressions - Exercises - Page 49: 53
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