Answer
$\frac{x^2+(x^2+3)^7}{(x^2+3)^4}$
Work Step by Step
$x^2(x^2+3)^{-4}+(x^2+3)^3=(x^2+3)^{-4}[x^2+(x^2+3)^{3-(-4)}]=\frac{x^2+(x^2+3)^7}{(x^2+3)^4}$
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