Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.3 - Solving Equations with Variables on Both Sides - Exercises - Page 23: 14

Answer

$t=1$.

Work Step by Step

The given equation is $\Rightarrow 2(2t+4)= \frac{3}{4}(24-8t)$ Use distributive property. $\Rightarrow 4t+8= 18-6t$ Add $6t-8$ to both sides. $\Rightarrow 4t+8+6t-8= 18-6t+6t-8$ Simplify. $\Rightarrow 10t= 10$ Divide both sides by $10$. $\Rightarrow \frac{10t}{10}=\frac{10}{10}$ Simplify. $\Rightarrow t=1$ Check:- $\Rightarrow 2(2(1)+4)= \frac{3}{4}(24-8(1))$ $\Rightarrow 2(2+4)= \frac{3}{4}(24-8)$ $\Rightarrow 2(6)= \frac{3}{4}(16)$ $\Rightarrow 12=12$ True. Hence, the solution is $t=1$.
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