Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.3 - Solving Equations with Variables on Both Sides - Exercises - Page 23: 20

Answer

One solution.

Work Step by Step

The given equation is $\Rightarrow 6d+8= 14+3d$ Subtract $3d$ from each side. $\Rightarrow 6d+8-3d= 14+3d-3d$ Simplify. $\Rightarrow 3d+8= 14$ Subtract $8$ from each side. $\Rightarrow 3d+8-8= 14-8$ Simplify. $\Rightarrow 3d= 6$ Divide both sides by $3$. $\Rightarrow \frac{3d}{3}=\frac{6}{3}$ Simplify. $\Rightarrow d= 2$ check:- $\Rightarrow 6(2)+8= 14+3(2)$ $\Rightarrow 12+8= 14+6$ $\Rightarrow 20= 20$ The statement $d=2$ is true. so, the equation has one solution.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.