Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.3 - Solving Equations with Variables on Both Sides - Exercises - Page 23: 21

Answer

One solution.

Work Step by Step

The given equation is $\Rightarrow 2(h+1)= 5h-7$ Use distributive property. $\Rightarrow 2h+2= 5h-7$ Subtract $2h$ from each side. $\Rightarrow 2h+2-2h= 5h-7-2h$ Simplify. $\Rightarrow 2= 3h-7$ Add $7$ to each side. $\Rightarrow 2+7= 3h-7+7$ Simplify. $\Rightarrow 9= 3h$ Divide both sides by $3$. $\Rightarrow \frac{9}{3}=\frac{3h}{3}$ Simplify. $\Rightarrow 3= h$ check:- $\Rightarrow 2(3+1)= 5(3)-7$ $\Rightarrow 2(4)= 15-7$ $\Rightarrow 8= 8$ The statement $h=3$ is true. so, the equation has one solution.
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