Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.3 - Solving Equations with Variables on Both Sides - Exercises - Page 23: 8

Answer

$r=1$.

Work Step by Step

The given equation is $\Rightarrow -3r+10=15r-8$ Add $3r+8$ to both sides. $\Rightarrow -3r+10+3r+8=15r-8+3r+8$ Simplify. $\Rightarrow 18=18r$ Divide both sides by $18$. $\Rightarrow \frac{18}{18}=\frac{18r}{18}$ Simplify. $\Rightarrow 1=r$. Check:- $\Rightarrow -3(1)+10=15(1)-8$ $\Rightarrow -3+10=15-8$ $\Rightarrow 7=7$ True. Hence, the solution is $r=1$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.