Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.3 - Solving Equations with Variables on Both Sides - Exercises - Page 23: 16

Answer

$x=\frac{1}{2}$.

Work Step by Step

The given equation is $\Rightarrow 2(4x+2)= 4x-12(x-1)$ Use distributive property. $\Rightarrow 8x+4= 4x-12x+12$ Simplify. $\Rightarrow 8x+4= -8x+12$ Add $8x-4$ to both sides. $\Rightarrow 8x+4+8x-4= -8x+12+8x-4$ Simplify. $\Rightarrow 16x= 8$ Divide both sides by $16$. $\Rightarrow \frac{16x}{16}=\frac{8}{16}$ Simplify. $\Rightarrow x=\frac{1}{2}$ Check:- $\Rightarrow 2(4(\frac{1}{2})+2)= 4(\frac{1}{2})-12((\frac{1}{2})-1)$ $\Rightarrow 2(2+2)= 2-12(\frac{1}{2}-1)$ $\Rightarrow 2(4)= 2-12(-\frac{1}{2})$ $\Rightarrow 8= 2+6$ $\Rightarrow 8= 8$ True. Hence, the solution is $x=\frac{1}{2}$.
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