Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.3 - Solving Equations with Variables on Both Sides - Exercises - Page 23: 15

Answer

$y=-12$.

Work Step by Step

The given equation is $\Rightarrow 10(2y+2)-y= 2(8y-8)$ Use distributive property. $\Rightarrow 20y+20-y= 16y-16$ Simplify. $\Rightarrow 19y+20= 16y-16$ Add $-16y-20$ to both sides. $\Rightarrow 19y+20-16y-20= 16y-16-16y-20$ Simplify. $\Rightarrow 3y= -36$ Divide both sides by $3$. $\Rightarrow \frac{3y}{3}=\frac{-36}{3}$ Simplify. $\Rightarrow y=-12$ Check:- $\Rightarrow 10(2(-12)+2)-(-12)= 2(8(-12)-8)$ $\Rightarrow 10(-24+2)+12= 2(-96-8)$ $\Rightarrow 10(-22)+12= 2(-104)$ $\Rightarrow -220+12= -208$ $\Rightarrow -208= -208$ True. Hence, the solution is $y=-12$.
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