College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.3 - Complex Numbers; Quadratic Equations in the Complex Number System - 1.3 Assess Your Understanding - Page 111: 21

Answer

$10-5i$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To simplify the given expression, $ (3-4i)(2+i) ,$ use the FOIL Method and the equivalence $i^2=-1.$ $\bf{\text{Solution Details:}}$ Using the FOIL Method which is given by $(a+b)(c+d)=ac+ad+bc+bd,$ the expression above is equivalent to\begin{array}{l}\require{cancel} 3(2)+3(i)-4i(2)-4i(i) \\\\= 6+3i-8i-4i^2 \\\\= 6-5i-4i^2 .\end{array} Since $i^2=-1,$ the expression above is equivalent to \begin{array}{l}\require{cancel} 6-5i-4(-1) \\\\= 6-5i+4 \\\\= 10-5i .\end{array}
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