College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises - Page 58: 101

Answer

$(x-3)(x+3)(x^{2}+9)$

Work Step by Step

We factor: $x^{4}-81=(x^{2})^{2}-9^{2}=(x^{2}-9)(x^{2}+9) =(x-3)(x+3)(x^{2}+9)$
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