College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises - Page 58: 136

Answer

$2(4x+5)^{2}(5x+1)(50x+31)$

Work Step by Step

We factor by grouping to obtain: $3(4x+5)^{2}* 4(5x+1)^{2}+(4x+5)^{3}* 2(5x+1)* 5 =2*6(4x+5)^{2}(5x+1)^{2}+2*5(4x+5)^{3}(5x+1) =2(4x+5)^{2}(5x+1)[6(5x+1)^1+5(4x+5)^1] =2(4x+5)^{2}(5x+1)(30x+6+20x+25) =2(4x+5)^{2}(5x+1)(50x+31)$
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