Answer
$(x-3)(7x-16)$
Work Step by Step
The trinomial $x^2-6x+9$ is a perfect square trinomial since the square of half of the middle term's coefficient, which is $(\frac{-6}{2})^2=(-3)^2$, is equal to the third term of the trinomial.
This means that the factored form of the trinomial is $(x-3)^2$.
Thus, the given expression is equivalent to:
$=7(x-3)^2+5(x-3)$
Factor out $x-3$ to obtain:
$=(x-3)[7(x-3)+5]
\\=(x-3)(7x-21+5)
\\=(x-3)(7x-16)$
