College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises - Page 58: 113

Answer

$-(3x-1)(3x+1)(x^{2}+1)$

Work Step by Step

We factor: $1-8x^{2}-9x^{4}$ First we rearrange the terms: $-9x^{4}-8x^{2}+1$ Next we factor out -1: $-(9x^{4}+8x^{2}-1)$ Next we factor in two parts: $-(9x^{2}-1)(x^{2}+1)$ Next we use the fact that $(a-b)(a+b)=a^2-b^2$ $-(3x-1)(3x+1)(x^{2}+1)$
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