Answer
$6(x+5)^{3}(x-1)(x+1)$
Work Step by Step
We factor by grouping to obtain:
$4(x+5)^{3}(x-1)^{2}+(x+5)^{4}* 2(x-1)
=2(x+5)^{3}(x-1)[2(x-1)^1+(x+5)^1]
=2(x+5)^{3}(x-1)(2x-2+x+5)
=2(x+5)^{3}(x-1)(3x+3)\\
=2* 3(x+5)^{3}(x-1)(x+1)
=6(x+5)^{3}(x-1)(x+1)$
