Answer
(3 - r)(9 + 3r + $r^{2}$)
Work Step by Step
27 - $r^{3}$ is a difference of cubes, so we write it as a difference of cubes and factor:
$3^{3}$ - $r^{3}$
(3 - r)($3^{2}$ + 3r + $r^{2}$)
= (3 - r)(9 + 3r + $r^{2}$)
College Algebra (11th Edition)
by Lial, Margaret L.; Hornsby John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671791
ISBN 13:
978-0-32167-179-0
Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises - Page 39: 62
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