Answer
b($b^{2}$ + 9b + 27)
Work Step by Step
$(b + 3)^{3}$ - 27 is a difference of cubes, so we write it as a diference of cubes and factor:
$(b + 3)^{3}$ - $3^{3}$
= (b + 3 - 3)($(b + 3)^{2}$ + (b + 3)(3) + $3^{2}$)
= b($b^{2}$ + 6b + 9 + 3b + 9 + 9)
= b($b^{2}$ + 9b + 27)
