Answer
$\frac{2(m^2+1)}{m^2-1}$
Work Step by Step
$\frac{(m+1)(m+1)+(m-1)(m-1)}{(m-1)(m+1)}$
$\frac{m^2+2m+1+m^2-2m+1}{m^2-1}$
$\frac{2m^2+2}{m^2-1}$
$\frac{2(m^2+1)}{m^2-1}$
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