College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.5 - Rational Expressions - R.5 Exercises - Page 48: 54

Answer

$\dfrac{6}{p-q}$

Work Step by Step

The given expression, $ \dfrac{4}{p-q}-\dfrac{2}{q-p} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{4}{p-q}-\dfrac{2}{-(p-q)} \\\\= \dfrac{4}{p-q}+\dfrac{2}{p-q} .\end{array} Since the fractions are similar, then copy the common denominator and add/subtract the numerators. Hence, the expression, $ \dfrac{4}{p-q}+\dfrac{2}{p-q} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{4+2}{p-q} \\\\= \dfrac{6}{p-q} .\end{array}
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