Answer
$15x^4-47x^2+28$
Work Step by Step
$$(5x^2-4)(3x^2-7)$$ $$=(5x^2\times 3x^2)+(5x^2\times (-7))+(-4\times 3x^2)+(-4\times (-7))$$ $$=15x^4-35x^2-12x^2+28$$ $$=15x^4-47x^2+28$$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4 - Page 61: 27
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