Answer
$14x^4y^2-19x^2y-3$
Work Step by Step
$$(7x^2y+1)(2x^2y-3)$$
To multiply two binomials (expressions with two terms) multiply each term in the first binomial by each term in the second binomial:
$$=(7x^2y\times 2x^2y)+[7x^2y\times (-3)]+(1\times 2x^2y)+[1\times (-3)]$$ $$=14x^4y^2-21x^2y+2x^2y-3$$
Combine like terms:
$$=14x^4y^2-19x^2y-3$$
