Answer
$9x^4-16x^2$
Work Step by Step
$$(3x^2+4x)(3x^2-4x)$$ $$=(3x^2\times 3x^2)+(3x^2\times (-4x))+(4x\times 3x^2)+(4x\times (-4x))$$ $$=9x^4-12x^3+12x^3-16x^2$$ $$=9x^4-16x^2$$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4 - Page 61: 38
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