College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4 - Page 61: 81

Answer

$49x^2y^4-100y^2$

Work Step by Step

$$(7xy^2-10y)(7xy^2+10y)$$ The product of the sum and the difference of two terms can be found using this formula: $(a-b)(a+b) = a^2-b^2$. $$=(7xy^2)^2-(10y)^2$$ $$=49x^2y^4-100y^2$$
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