Answer
$16x^4-8x^2+1$
Work Step by Step
$$(4x^2-1)^2$$ $$=(4x^2-1)(4x^2-1)$$ $$=(4x^2\times 4x^2)+(4x^2\times (-1))+(-1\times 4x^2)+(-1\times (-1))$$ $$=16x^4-4x^2-4x^2+1$$ $$=16x^4-8x^2+1$$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4 - Page 61: 47
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