Answer
$9x^2y^4-16y^2$
Work Step by Step
$$(3xy^2-4y)(3xy^2+4y)$$ The product of the sum and the difference of two terms can be found using this formula: $(a-b)(a+b) = a^2-b^2$. $$=(3xy^2)^2-(4y)^2$$ $$=9x^2y^4-16y^2$$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4 - Page 61: 82
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