Answer
$(x^2+4)\sqrt{x}$
Work Step by Step
Factor each radicand so that one of the factors is a perfect square to obtain:
$=\sqrt{16(x)} +\sqrt{x^4(x)}
\\=\sqrt{4^2(x)}+\sqrt{(x^2)^2(x)}$
Simplify each radical to obtain:
$=4\sqrt{x} + x^2\sqrt{x}$
Combine like radicals to obtain:
$=(4+x^2)\sqrt{x}
\\=(x^2+4)\sqrt{x}$
