Answer
(a) $16a^{4}b^{2}$
(b) $8w^6z^{9/8}$
Work Step by Step
(a) $(64a^{6}b^{3})^{2/3}=64^{2/3}a^{6*2/3}b^{3*2/3}=16a^{4}b^{2}$
(b) $(16w^{8}z^{3/2})^{3/4}=16^{3/4}w^{8*3/4}z^{(3/2)(3/4)}=8w^6z^{9/8}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises - Page 30: 64
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
