Answer
(a) 9
(b) $\frac{1}{7}$
(c) $\frac{1}{36}$
Work Step by Step
(a) $3^{2/7}*3^{12/7}=3^{2/7+12/7}=3^{2}=9$
(b) $\frac{7^{2/3}}{7^{5/3}}=7^{2/3-5/3}=\frac{1}{7}$
(c) $(\sqrt[5]{6})^{-10}=(6^{1/5})^{-10}=\frac{1}{36}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises - Page 30: 54
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