Answer
$6\sqrt{x^2+y^2}$
Work Step by Step
Factor the radicand so that one of the factors is a perfect square to obtain:
$=\sqrt{36(x^2+y^2)}
\\=\sqrt{6^2(x^2+y^2)}$
Simplify the radical to obtain:
$=6\sqrt{x^2+y^2}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises - Page 30: 48
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