Answer
14
Work Step by Step
Using $x=3, y=4, z=-1$ and plugging into the equation, we get:
$(9x)^{2/3}+(2y)^{2/3}+z^{2/3}=(9*3)^{2/3}+(2*4)^{2/3}+(-1)^{2/3}=(3^{3})^{2/3}+(2^{3})^{2/3}+(1)^{1/3}=3^{2}+2^{2}+1=9+4+1=14$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises - Page 30: 57
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
