Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 6 - Linear Transformations - 6.6 Chapter Review - Additional Problems - Page 430: 13

Answer

$T(x)=(-\frac{1}{2}x, \frac{5}{2}x,0,-x)$

Work Step by Step

We are given $T(2)=\begin{bmatrix} -1 & 5 & 0 & 2 \end{bmatrix}$ Since $T(x)=\frac{x}{2}.T(2)\\ =\begin{bmatrix} -1 & 5 & 0 & 2 \end{bmatrix}\frac{1}{2}\begin{bmatrix} x \end{bmatrix}\\ =(-\frac{1}{2}x, \frac{5}{2}x,0,-x)$ Hence, $T(x)=(-\frac{1}{2}x, \frac{5}{2}x,0,-x)$
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