Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 6 - Linear Transformations - 6.6 Chapter Review - Additional Problems - Page 430: 28

Answer

See below

Work Step by Step

Consider $V_1 \cong V_2\\ V_2 \cong V_3$ then there exist isomorphisms $T_1:V_1 \rightarrow V_2\\ T_2: V_2 \rightarrow V_3$ We have: $T_2T_1:V_1 \rightarrow V_3$ Since $T_1 \& T_2$ are both one-to-one and onto, so $T_2T_1$ is also one-to-one and onto. Consequently, $T_2T_1$ is also an isomorphism. Hence, $V_1 \cong V_3$
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