Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.1 - Rational Numbers: Multiplication and Division - Problem Set 2.1 - Page 48: 1

Answer

$\dfrac{2}{3}$

Work Step by Step

Cancelling the common factor between the numerator and the denominator, the given expression, $ \dfrac{8}{12} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{4}\cdot2}{\cancel{4}\cdot3} \\\\= \dfrac{2}{3} \end{array}
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